std::countl_one
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                    |   Defined in header  <bit>
  | 
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|   template< class T > constexpr int countl_one( T x ) noexcept;  | 
(since C++20) | |
Returns the number of consecutive 1 ("one") bits in the value of x, starting from the most significant bit ("left").
This overload participates in overload resolution only if T is an unsigned integer type (that is, unsigned char, unsigned short, unsigned int, unsigned long, unsigned long long, or an extended unsigned integer type).
Parameters
| x | - | value of unsigned integer type | 
Return value
The number of consecutive 1 bits in the value of x, starting from the most significant bit.
Notes
| Feature-test macro | Value | Std | Feature | 
|---|---|---|---|
__cpp_lib_bitops | 
201907L | 
(C++20) | Bit operations | 
Example
Run this code
#include <bit> #include <bitset> #include <cstdint> #include <iostream> int main() { for (const std::uint8_t i : {0, 0b11111111, 0b01111111, 0b11100011}) std::cout << "countl_one( " << std::bitset<8>(i) << " ) = " << std::countl_one(i) << '\n'; }
Output:
countl_one( 00000000 ) = 0 countl_one( 11111111 ) = 8 countl_one( 01111111 ) = 0 countl_one( 11100011 ) = 3
See also
|    (C++20)  | 
  counts the number of consecutive 0 bits, starting from the most significant bit  (function template)  | 
|    (C++20)  | 
  counts the number of consecutive 0 bits, starting from the least significant bit  (function template)  | 
|    (C++20)  | 
  counts the number of consecutive 1 bits, starting from the least significant bit  (function template)  | 
|    (C++20)  | 
  counts the number of 1 bits in an unsigned integer  (function template)  | 
|    (C++20)  | 
  checks if a number is an integral power of 2  (function template)  | 
|   returns the number of bits set to true  (public member function of std::bitset<N>)  | |
|   checks if all, any or none of the bits are set to true  (public member function of std::bitset<N>)  |